Draw a figure based on given instructions:
In the figure, AC be the tower and AB be the canal.
Let AC = h, AB = x and BD = y
From right △CBA:
cot 60° = x/h
1/√3 = x/h
or x = h/√3
From right △CAD:
cot 30° = (x+y)/h
√3 = (x+y)/h
y = 2h/√3
Since y distance is covered in 6 seconds, then x distance is covered in 6x/y seconds
Substituting the values of x and y, we get
6x/y = (6h/√3)/ (2h/√3)
= 3
Therefore, time taken by the car to reach the foot of the tower form this point is 3 seconds.