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0 votes
34.1k views
in Physics by (45.7k points)

A current of 1 A is drawn by a filament of an electric bulb. Number of electrons passing through a cross-section of the filament in 16 seconds would be roughly 

(a) 1020 

(b) 1016 

(c) 1018 

(d) 1023

1 Answer

+1 vote
by (46.2k points)
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Best answer

The answer is (a) 1020

I = Q/t 

Q = It 

Q= 1 x 16 

Q= 16q 

Q= ne 

n = Q/e

n = 16 /1.6 x 10-19

n = 10 x 1019 

n = 1020 electrons

The number of electrons flowing is 1020 electrons

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