Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
50.1k views
in Surface Areas And Volumes by (44.3k points)

A solid metallic sphere of diameter 21 cm is melted and recast into a number of smaller cones, each of diameter 3.5 cm and height 3 cm. Find the number of cones so formed.

1 Answer

+1 vote
by (58.8k points)
selected by
 
Best answer

Diameter of sphere = 21 cm

Radius = 21/2 cm

Height of the cone = 3 cm

Radius of the cone = 7/4 cm

Volume of the sphere = 4/3 πr3 = 4/3 x π x (21/2)3 cm3

Volume of cone = 1/3 πr2 h = 1/3 π (7/4)2 x 3 cm3

Let n be the number of cone formed, then

n = (Volume of the sphere) / (Volume of cone)

n = (4/3 x π x (21/2)3) / (1/3 π (7/4)2 x 3)

= 504

Number of cones formed = 504

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...