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in Physics by (46.2k points)

A current of 1 ampere flows in a series circuit containing an electric lamp and a conductor of 5 Ω when connected to a 10 V battery. Calculate the resistance of the electric lamp. Now if the resistance of 10 Ω is connected in parallel with this series combination, what change (if any) in current flowing through 5 Ω conductor and potential difference across the lamp will take place? Give reason.

1 Answer

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by (45.7k points)
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Best answer

(1) 

Let R be the resistance of the electric lamp. In series total resistance = 5 + R 

I = v/r 

1 = 10/5 + R 

R = 5 ohm 

2) V across Lamp + conductor = 10 V

V across Lamp = I × R 

= 1 x 5 

= 5 Volt

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