Consider two lines AB and CD intersecting at a point O with ∠AOC = 90o
From the figure we know that ∠AOC and ∠BOD are vertically opposite angles
∠AOC = ∠BOD = 90o
From the figure we also know that ∠AOC and ∠AOD form a linear pair
So it can be written as
∠AOC + ∠AOD = 180o
Substituting the values
90o + ∠AOD = 180o
On further calculation
∠AOD = 180o – 90o
By subtraction
∠AOD = 90o
From the figure we also know that ∠BOC = ∠AOD are vertically opposite angles
∠BOC = ∠AOD = 90o
Therefore, it is proved that each of the remaining angle is 90o