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in Differential Equation by (47.9k points)

Solve the differential equations (1 + e(x/y))dx + e(x/y)(1 + x/y)dy = 0

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(1 + e(x/y))dx + e(x/y)(1 + x/y)dy = 0

Thus f (x, y) is homogeonous function.

∴ Given differential equation is homogeneous

Putting x = vy …..(2)

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