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Solve the differential equations dy/dx = (6x - 2y - 7)/(2x + 3y - 6)

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Solve the differential equations dy/dx = (6x - 2y - 7)/(2x + 3y - 6)

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dy/dx = (6x - 2y - 7)/(2x + 3y - 6)

h and are such that

6h - 2k - 7 = 0 and 2h + 3k - 6 = 0

Putting these value in equation (1)

h = 3/2, k = 1

Solving two equation,

dy/dx = (6x - 2y)/(2x + 3y)

Which is homogeneous equation. 

Then y = vx

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