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in Surface Areas And Volumes by (44.3k points)

Find the capacity of a closed rectangular cistern whose length is 8m, breadth 6m and depth 2.5m. Also, find the area of the iron sheet required to make the cistern.

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The dimensions of the cistern are

Length = 8m

Breadth = 6m

Height = 2.5m

We know that

Capacity of cistern = volume of cistern

Volume of cistern = l × b × h

By substituting the values

Volume of cistern = 8 × 6 × 2.5

By multiplication

Volume of cistern = 120m3

We know that the area of iron sheet required is equal to the total surface area of the cistern

So we get

Total surface area = 2 (lb + bh + lh)

By substituting the values

Total surface area = 2 (8 × 6 + 6 × 2.5 + 2.5 × 8)

On further calculation

Total surface area = 2 (48 + 15 + 20)

So we get

Total surface area = 2 × 83 = 166 m2

Therefore, the capacity of the cistern is 120 m3 and the area of the iron sheet required to make the cistern is 166m2.

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