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in Surface Areas And Volumes by (58.8k points)

In a water heating system, there is a cylindrical pipe of length 28m and diameter 5cm. Find the total radiating surface in the system.

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Best answer

The dimensions of cylindrical pipe

Diameter = 5cm

Radius = 5/2 = 2.5cm

Height = 28m = 2800cm

We know that

Total radiating surface in the system = curved surface area of cylindrical pipe = 2 πrh

By substituting the values

Total radiating surface in the system = 2 × (22/7) × 2.5 × 2800

So we get

Total radiating surface in the system = 44000 cm2

Therefore, the total radiating surface in the system is 44000 cm2.

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