(i) We know that
Cost of painting inner curved surface of the vessel = cost of painting per m2 × inner curved surface of vessel
By substituting the values
3300 = 30 × Inner curved surface of vessel
On further calculation
Inner curved surface of vessel = 110 m2
(ii) Consider r as the inner radius of the base
It is given that depth = 10m
We know that
Inner curved surface of vessel = 2 πrh
By substituting the values
110 = 2 × (22/7) × r × 10
So we get
r = (110 × 7)/ (2 × 22 × 10)
r = 1.75m
(iii) We know that
Capacity of the vessel = πr2h
By substituting the values
Capacity of the vessel = (22/7) × (1.75)2 × 10
So we get
Capacity of the vessel = 96.25 m3