It is given that
Internal radius of the hemispherical bowl = 4cm
Thickness of the hemispherical bowl = 0.5cm
We know that
External radius = 4 + 0.5 = 4.5 cm
We know that
Volume of steel used in making the hemispherical bowl = volume of the shell
So we get
Volume of steel used in making the hemispherical bowl = 2/3 π (4.53 – 43)
On further calculation
Volume of steel used in making the hemispherical bowl = 2/3 × (22/7) × [91.125 – 64]
We get
Volume of steel used in making the hemispherical bowl = 2/3 × (22/7) × 27.125 = 56.83 cm3
Therefore, the volume of steel used in making the bowl is 56.83 cm3.