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If x3 + mx2 + nx + 6 has x - 2 as a factor and leaves a remainder 3, when divided by x - 3, find the values of m and n.

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Let p(x) = x3 + mx2 + nx + 6 be the given polynomial. Then, (x - 2) is a factor of p(x)

It is given that p(x) leaves the remainder 3 when it is divided by (x - 3). Therefore.

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