Question

In a cricket match, a batsman hits a boundary 6 times out of 3 balls he plays. Find the probability that he did not hit a boundary.

Answer 1

It is given that

Number of times boundary was hit = 6

Total number of balls played = 30

So we get

Number of times boundary was not hit = 30 – 6 = 24

We know that

Probability that the batsman did not hit a boundary = number of times boundary was not hit/ total number of balls played

By substituting the values

Probability that the batsman did not hit a boundary = 24/30

By division

Probability that the batsman did not hit a boundary = 4/5 = 0.8