When a pair of dice in thrown
∴ Number of all possible outcomes
n(S) = 6 × 6 = 36
Number of doublets can be make from a pair of dice = 6
[(1,1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)]
∴ Probability that doublet are find
P = 6/36 = 1/6 and probability that doublets are not find q = 1 – p
= 1 – 1/6 = 5/6
A pair of dice is thrown four times
∴ n = 4
