From the figure
Using the Pythagoras theorem in △ RTQ
We get
RT2 + TQ2 = RQ2
By substituting the values
RT2 + 82 = 172
On further calculation
RT2 = 172 – 82
So we get
RT2 = 289 – 64
By subtraction
RT2 = 225
By taking square root
RT = √ 225
RT = 15cm
We can find the area of trapezium
Area of trapezium PQRS = ½ (sum of parallel sides × distance between them)
So we get
Area of trapezium PQRS = ½ ((8 + 16) × 15)
On further calculation we get
Area of trapezium PQRS = 180 cm2
Therefore, the area of trapezium PQRS is 180 cm2.