(i) {a, b} ⊂ {b, a, c}
Elements of first set (a, b) is present in second set.
Hence, the statement is true.
(ii) {a, e} ⊂ {x : x is vowel of English alphabet}
Tabular form of seconds set is {a, e, i, o, u}
Elements of first set (a, e is present is second set.
Hence, the statement is true.
(iii) {1, 2, 3} ⊄ {1, 3, 2, 5}
Elements of first set is also the elements of seconds set.
Hence, the statement is false.
(iv) {x : x is an even natural number less then 6} ⊂ (x : x is a natural number which divide 36}
{2, 4} ⊂ {1, 2, 3, 4, 6, 9, 12, 18, 36}
Hence, the statement is true.