Given,
A = {a, b, c, d}, B = {p, q, r}, C = {a, b, p, q}
(i) (A – B) = C
L.H.S. = A – B = {a, b, c, d} – {p, q, r} = {a, b, c, d}
⇒ A – B ≠ C (False)
(ii) B – C ≠ A
B – C = {p, q, r,} – {a, b, p, q} = {r} ≠ A (True)
(iii) B – A = Φ
B – A = {p, q, r,} – {a, b, c, d}
= {p, q, r} ≠ Φ (False)
(iv) (A ∪ B) – C
A ∪ B = {a, b, c, d} ∪ {p, q, r} = {a, b, c, d, p, q, r}
(A ∪ B) – C = {a, b, c, d, p, q, r} – {a, b, p, q}
= {c, d, r,} (True)
(v) (A ∪ B) ∩ C = C
From A ∪ B = {a, b, c, d, p, q, r}
(A ∪ B) ∩ C = {a, b, c, d, p, q, r} ∩ {a, b, p, q}
= {a, b, p, q} = C (True)