Question

In the adjoining figure, CE || AD and CF || BA. Prove that ar (△ CBG) = ar (△ AFG).

Answer 1

From the figure we know that △ BCF and △ ACF lie on the same base CF between the same parallels CF and BA

So we get

Area of △ BCF = Area of △ ACF

By subtracting △ CGF both sides

Area of △ BCF – Area of △ CGF = Area of △ ACF – Area of △ CGF

So we get

Area of △ CBG = Area of △ AFG

Therefore, it is proved that ar (△ CBG) = ar (△ AFG).