Answer is (D)
Here, f1 = {(x, y) : y = x + 1}
= {(1, 2), (2, 3), (3, 4)}
f2 = {(x, y) : x + y > 4}
= (1, 4), (2, 3), (2, 4), (3, 2), (3, 3), (3, 4), (4, 1), (4, 2), (4, 3), (4, 4)}
f3 = {(x, y) : y < x}
= {(2, 1), (3, 1), (3, 2), (4, 1), (4, 2), (4, 3)}
f4 = {(x, y) : x + y = 5}
= {(x, y) : x = 5 – y}
= {(1, 4), (2, 3), (3, 3), (4, 1)}
It is clear that only f4 is a function because every element of A correspoints to unique element in B.