Answer is (C)
f(x) = x3
Given, f : R → R and f(x) = x3
Let y ∈ R (co-domain) if possible, then let pre-image of y is x in domain R, then
f(x) = y
⇒ x3 = y
⇒ x = y1/3 ∈ R ∀ y ∈ R
So, pre-image of each value of y is exist in domain R.
So, R is onto function.