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0 votes
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in Relations and Functions by (48.0k points)

Range of function f(x) = cos(x/3) is

(A) (0, ∞)

(B) (-1/3, 1/3)

(C) [-1, 1]

(D) [0, 1]

1 Answer

+1 vote
by (46.3k points)
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Best answer

Answer is (C)

Let y = cos(x/3)​​​

-1 ≤ cos(x/3)​​​ ≤ 1

-1 ≤ y ≤ 1

x is defined if -1 ≤ y ≤ 1

Hence, required range = [-1, 1]

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