Let √3 − √2 = r where r be a rational number
Squaring both sides
⇒ (√3-√2)2= r2
⇒ 3 + 2 - 2 √6 = r2
⇒ 5 - 2 √6 = r2
Here, 5 - 2√6 is an irrational number but r2 is a rational number
∴ L.H.S. ≠ R.H.S.
Hence it contradicts our assumption that √3 − √2 is a rational number.