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in Squares And Square Roots by (44.3k points)

Without adding, find the sum (1+3+5+7+9+11+13+15+17+19).

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Given (1+3+5+7+9+11+13+15+17+19) According to the property of perfect square, for any natural number n, we have sum of first n odd natural numbers = nBut here n = 10 Applying the above law we get

Therefore (1+3+5+7+9+11+13+15+17+19) = 10= 100

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