Firstly we have to find the factors for the above numbers
∛1152 = \(\sqrt[3]{(2 × 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3)}\) = 4\(\sqrt[3]{( 2 × 3 × 3)}\)
∛1331 = \(\sqrt[3]{(11 × 11 × 11)}\)
∛2016 = \(\sqrt[3]{(2 × 2 × 2 × 2 × 2 × 3 × 3 × 7)}\) = 2 \(\sqrt[3]{(2 × 2 × 3 × 3 × 7)}\)
∛739 = no prime factors can be found.
From the above results, 1331 has the perfect cube factors.
∴ 1331 is the perfect cube.
