Question

Write the principal argument of -2.

Answer 1

-2 = -2 + 0i

Let -2 + 0i = r(cos θ + i sin θ)

⇒ r cos θ = -2 ….(i)

r sin θ = 0 ………(ii)

⇒ tan θ = 0/-2  = 0

Hence, principal argument of -z is π.