Total number of points on side AB, BC and CA = 3 + 4 + 5 = 12
Hence, number of triangles formed by 12 points
Now, there are 3 points on side AB.
Hence, number of triangle formed by these points
These are 4 points on side BC.
Hence, number of triangles formed by these points
There are 5 points on side CA.
Hence, number of triangle formed by these points
Points on sides AB, BC and CA are collinear.
Hence, any triangle cannot be formed by these points
Hence, total number of required triangles = 220 – 1 – 4 – 10 = 205.