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in Permutations and Combinations by (48.0k points)

A box contains two white, three black and four red balls. Determine the number of ways in which three balls can be selected from this box, in which at least one black ball is compulsory.

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Total number of balls in the box = 2 + 3 + 4 = 9

For at least one black ball we can choose it in the following ways.

Total number of permutation according to the table

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