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in Sequence, Progression, and Series by (46.2k points)

If sum of m A.P. of n terms are S1, S2 and S3…, Sm respectively. Their first term are 1, 2, 3,…., m respectively and common difference 1, 3, 5,…., (2m – 1) respectively, then prove that
S1 + S2 + S3 + … + Sm= mn/2 (mn + 1)

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= n/2[n.m2 + m] = mn/2[mn + 1]

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