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0 votes
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in Physics by (10.8k points)

In byju's I have seen that to derive the equation v2u2  ​​​​​​= 2as we just have to put we just have to put the value of t ​​​​​{ (v-u) / a } in place of t in the equation s = ut + 1/2 at2 but the problem is I am not able to simplify it to get the 3rd equation of motion.

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1 Answer

+1 vote
by (1.7k points)

we know : displacement = area under the velocity time graph .
S= area of trapezium ACEF
S= 1/2 ( b¹ + b² ) h
s= 1/2 ( AF+CE )FE
S= 1/2 ( U+ V) T
We know -v= u+ at
v-u/a= t
now 2 in 1
S= 1/2( v+u) (v-u)
2as= ( v+u) (v-u)
2as=v²-u²
[v² - u2 = 2as]

hope it will help u

we know : displacement = area under the velocity time graph .
S= area of trapezium ACEF
S= 1/2 ( b¹ + b² ) h
s= 1/2 ( AF+CE )FE
S= 1/2 ( U+ V) T
We know -v= u+ at
v-u/a= t
now 2 in 1
S= 1/2( v+u) (v-u)
2as= ( v+u) (v-u)
2as=v²-u²
[v² - u2 = 2as]image

Hope it will help:

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