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Solve: (3t-2)/4-(2t+3)/3=2/3-t

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Solve: (3t-2)/4-(2t+3)/3=2/3-t

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Given (3t-2)/4-(2t+3)/3=2/3-t

Now by taking L.C.M for 4 and 3 is 12

(3(3t-2)-4(2t+3))/12=2/3-t

By transposing the above equation we can write as

(9t-6-8t-12)/12=2/3-t

Again by transposing

t=26/13

t=2

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