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Solve: (5x-4)/6=4x+1-(3x+10)/2

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Solve: (5x-4)/6=4x+1-(3x+10)/2

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Given (5x-4)/6=4x+1-(3x+10)/2

Now by taking L.C.M for 1 and 2 is 1

5x-4-6(4x+1) + 3(3x+10)/6=0

By cross multiplication we get

5x-4-6(4x+1) + 3(3x+10) = 0

-10x=-20

Again by transposing,

x=20/10=2

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