Let the three consecutive numbers be (2x+1), (2x+3) and (2x+5)
According to the question we can write as 2x+1+2x+3+2x+5=147
On simplifying we get 6x+9=147
On rearranging we get
6x=147-9
6x=138
x=138/6=23
So the numbers are (2x+1)=47
(2x+3)=49
(2x+5)=51
