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ABCD is a parallelogram in which ∠A = 110°. Find the measure of each of the angles ∠B, ∠C and ∠D.

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Given ∠A = 110o

But we know that sum of adjacent angles of a parallelogram is 180o

∠A + ∠B = 180o

110o+ ∠B = 180o

∠B = 180o– 110o= 70o.

Also ∠B + ∠C = 180[Since ∠B and ∠C are adjacent angles]

70o+ ∠C = 180o

∠C = 180o– 70o= 110o.

Now ∠C + ∠D = 180[Since ∠C and ∠D are adjacent angles]

110o+ ∠D = 180o

∠D = 180o– 110o= 70o

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