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The length of the diagonals of a rhombus are 16cm and 12cm. The length of each side of the rhombus is

(a) 8 cm (b) 9 cm (c) 10 cm (d) 12 cm

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(c) 10 cm


Let ABCD be rhombus with AC and BD diagonals.

Let AC and BD bisect at O.

Therefore AO = 16/2=8

BO = 12/2=6cm

In right angled triangle AOB, by Pythagoras theorem we can write as



AB2= 64 + 36

AB= √ 100

AB =10

Length of rhombus is 10 cm

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