(i) 2y = mx + c
⇒ y = mx/2 + c/2
⇒ y = (m/2)x + c/2 ....(i)
Comparing with y = m1x + c1
m1 = m/2
4y = 2 mx
Thus, both lines will be parallel.
(ii) x cos α + y sin α = p
⇒ y sin α = – x cos α + p
We see that
m1 = m2 = – cot α
Therefore both line will be parallel.