Question

Find the equation of line which passes through a point (0,1) and intercept cut by line at axis as 3 times the intercept cut at y-axis.

Answer 1

Let equation of line

x/10 + y/10 = 1 …(i)

Given that intercept of x-axis is 3 times the intercept of y-axis

a = 3b

Putting a = 3b in eq.ⁿ (i)

x/3b + y/b = 1

⇒ x + 3y = 3b

But it passes through point (0, 1)

∴ 0 + 3 (1) = 3b

⇒ b = 1

∴ a = 3 (1) = 3

∴ a = 3, b = 1

From eq.ⁿ (ii) x + 3y = 3 × 1

Thus, required equation of line

⇒ x + 3y = 3