Question

A bag contains 6 white, 7 red and 5 black balls. Out of these 3 balls are randomly chosen one by one.What will be the probability that three balls are white,whereas the ball drawn is not replaced back ?

Answer 1

Probability to draw 1 ball out of 6 white balls whereas total balls are 18

= ⁶C₁/¹⁸C₁ = 6/18 = 1/3

In second attempt

Probability to draw 1 ball out of 5 white ball whereas total balls are 17

= ⁵C₁/¹⁷C₁ = 5/17

In third attempt

Probability to draw 1 ball out of 4 white balls whereas total balls are 16.

= ⁴C₁/¹⁶C₁ = 4/16 = 1/4

Thus, total probability that all the three balls are while.