In throwing a dice, obtained sample spapce
S = {1,2, 3, 4, 5, 6}, n(S) = 6
(i) Event E, appear a prime number
then E = {2, 3, 5}
Thus n(E) = 3
Then probability of event E
P(E) = n(E)/n(S)
= 3/6 = 1/2
Thus, probability to get a prime number is = 1/2
(ii) Event to get number 1 or less than 1
B = {1}
Then n(B) = 1
Thus, probability to get 1 or less than 1
P(B) = n(B)/n(S) = 1/6
Thus, probability to get no. 1 or less than 1 = 1/6
(iii) Event to appear no. less than 6
D = {1,2, 3,4,5}
then n(D) = 5
Then, probability to appear no. less than 6.
P(D) = n(D)/n(S) = 5/6
Thus, probability to get number less than 6 = 5/6