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If three coin are tossed and E be the event to getting at least one head, then n(E) will be –

(A) 6

(B) 3

(C) 4

(D) 8

1 Answer

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Answer is (C) 4

S = {HHH, HHT, HTH, HTT, THH, THT, TTH, ITT)

n(E) = 4

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