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If 5 digit numbers are formed by using digit 1,2,3,4, 5,6 and 8, then probability to get even digit at both end will be –

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If 5 digit numbers are formed by using digit 1,2,3,4, 5,6 and 8, then probability to get even digit at both end will be –

(A) 5/7

(B) 4/7

(C) 3/7

(D) 2/7

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Answer is (D) 2/7

No. of total digits = 7

Even number appear on both end so, favourable cases = 2

Thus, required probability = 2/7

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