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There are 12 sections in a group, in which four sections are faulty 3 sections are randomly drawn one by one. Without replacement probability to get no. one as faulty is –

(A) 3/55

(B) 13/55

(C) 14/55

(D) 17/55

1 Answer

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Best answer

Answer is (C) 14/55

Total terms = 12, Non-facility sections = 12 -4 = 8

Faulty section = 4

Probability to get no. one as fault in three attempt is –

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