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A family having 3 children in which at least one boy, then probability that family have one boy and one girl is –

(A) 1/2

(B) 1/3

(C) 1/4

(D) 3/4

1 Answer

+1 vote
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Best answer

Answer is (B) 1/3

Sample space of children in a family is :

S = {B, G, G, B, B, G, B, B, G}

Event of 2 boys and 1 girl A = {B, B, G}

∴ n(S) = 3, n(A) = 1

Thus, required probability = n(A)/n(S) = 1/3

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