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In a non-leap year. Find the probability to getting 53 Mondays.

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In a non-leap year. Find the probability to getting 53 Mondays.

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There are 52 Sundays in a leap year and 2 days are remains. 

If one of them is Sunday, then there will be 53 Sundays.

Now, probability that at least two days one of them is Sunday = 1/7

∴ Required probability = 1/7

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