Question

There are 6 red and 8 black balls in a bag. 4 balls are taken out two times, 4 balls taken once are replaced back. What will be the probability that 4 balls in first attempt be red and in second attempt be black ?

Answer 1

Total balls = 6 + 8 = 14

Since ball are replaced

∴ Probability to draw 4 red ball in 1st chance and 4 black balls in 2nd chance.