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In throwing two dices, what is the probability that neither same digit appear nor sum of digit be 9 ?

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Best answer

Total events in throwing two dices simultaneously

n(S) = 62 = 36

Total events to get same digit at two dices and sum 9

A = {(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6), (3, 6), (4, 5), (5, 4), (6, 3)}

n(A) = 10

Probability to get same digit on dices or sum 9

= n(A)/n(S) = 10/36

= 5/18

Thus, required probability

= 1 - 5/18 = 13/18

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