Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
5.6k views
in Laws of Motion by (49.6k points)
closed by

A cyclist speeding at 18 km/h on a level road takes a sharp circular turn of radius 3 m without reducing the speed. The coefficient of static friction between the tyres and the road is 0. 1. Will the cyclist slip while taking the turn?

1 Answer

+1 vote
by (34.7k points)
selected by
 
Best answer

Given; v = 18km/h = 18 × \(\frac{5}{18}\) = 5 m/s,
r = 3m
μs = 0.1; g = 9.8 m/s2
The limiting friction available to cyclist,
fs = μsN = μsmg
Required centripetal force,

Therefore, cyclist will slip on the turn and fall down.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...