Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
993 views
in Work, Energy and Power by (34.7k points)
closed by

A mass of 2.5 kg is hung on a steel wire. This increases 0.25 cm in its length. Determine the work done to pull the wire. (g = 10 m/s2) [Hint: Mg = kx, W = \(\frac{1}{2}\) kx2]

1 Answer

+1 vote
by (49.6k points)
selected by
 
Best answer

Given; F = 2.5 xg = 2.5 × 10 = 25 N
x = 0.25 cm = 0.25 x 10-2 m = 2.5 x 10-3 m
If the force constant of the wire be k, then
\(F=k x \Rightarrow k=\frac{F}{x}=\frac{25}{2.5 \times 10^{-3}}=10^{4} \mathrm{N} \cdot \mathrm{m}^{-1}\)

∴ The work done in pulling the wire,
W = \(\frac{1}{2}\) kx2\(\frac{1}{2}\) × 104 × 2.5 x 2.5 x 10-6
\(\frac{1}{2}\)× 6.25 × 10-2
= 3.125 x 10-2 J = 0.03125 J

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...