Question

Find the additive inverse of:

(i) 5

(ii) -9

(iii) (3/14)

(iv) (-11/15)

(v) (15/-4)

(vi) (-18/-13)

(vii) O

(viii) (1/-6)

Answer 1

(i) 5

Additive inverse of 5 is -5

(ii) -9

Additive inverse of -9 is 9

(iii) (3/14)

Additive inverse of (3/14) is (-3/14)

(iv) (-11/15)

Additive inverse of (-11/15) is (11/15)

(v) (15/-4)

First we write each of the given numbers with a positive denominator.

(15/-4) = [(15× (-1))/ (-4×-1)]

= (-15/4)

Then,

Additive inverse of (-15/4) is (15/4)

(vi) (-18/-13)

First we write each of the given numbers with a positive denominator.

(-18/-13) = [(-18× (-1))/ (-13×-1)]

= (18/13)

Then,

Additive inverse of (18/13) is (-18/13)

(vii) O

Additive inverse of 0 is 0

(viii) (1/-6)

First we write each of the given numbers with a positive denominator.

(1/-6) = [(1× (-1))/ (-6×-1)]

= (-1/6)

Then,

Additive inverse of (-1/6) is (1/6)