Since the least numbers of a room are required.
So, number of participants in each room must be the H.C.F. of 60, 84, and 108.
60 = 22 × 3 × 5
84 = 22 × 3 × 7
and 108 = 22 × 33
HCF of 60, 84 and 108 = 22 × 3 = 4 × 3 = 12
Therefore, in each room 12 participants can be seated