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+1 vote
2.5k views
in Laws of motion by (1.3k points)
edited by

As shown in figure, A is a man of mass 60kg standing on a block of mass 40kg kept on ground. The coefficient of friction between the feet of the man and the block is 0.3 and that between B and the ground is 0.2. If the person pulls the string with 125N force, then

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2 Answers

+3 votes
by (65.0k points)
edited by

Lets start with calculating frictional forces.
Frictional force between man and block

Tension in the string T=125 N

Since, frictions forces on the block is more than the force applied by the man. Therefore, there will not be any motion.

Friction acting between A and B =f1 =180 N

by (1.3k points)
+1
Can you send me the solution with FBD of block and man
by (1.3k points)
+1
After that I am able to understand.
+1 vote
by (1.7k points)

Is this FBD good to you:

FBD

Correct option (A) (B) (C) 

Explanation:

image

by (1.7k points)
+2
Hope you now understand.
by (65.0k points)
–1
please check your solution as per question data
by (1.7k points)
+1
Hé salope qui m'apprend à écrire.
Vous avez déjà copié mon FBD.
by (1.7k points)
+1
Tu es des conneries.
by (63.2k points)
edited by
+2
Hello @sone, Please do not use slang words in another language. You should respect everyone's thoughts and act politely.

You should rather ask her if you have any question about her comment. It's very sad that you are behaving like this.
by (1.7k points)
Hey bro firstly she is copied my diagram and then scolding me.
Hiw would you feel if this would be done with you
by (1.7k points)
I'm sorry.
For behaviour.
Hope so You would able forgive me.
by (1.7k points)
Sorry
Actually I got irritated to that
Sorry
by (63.2k points)
+1
Happy that you understood :)

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